SECTION IX
REGULATION OF GENE EXPRESSION
(AN OPTIONAL EXERCISE)
Introduction and Background Comments.....................…..2
Protocol..............................................................................….3
Optional Experiment.......................................................…..6
For Thought and Discussion...........................................…..9
A. INTRODUCTION
A characteristic of all living organisms is the ability to respond to changes in the environment around them. Ultimately, this response is due to changes at the molecular level: examples include signal transduction and amplification, regulation of networks of biochemical reactions by enzyme allostery and/or control of the de novo production of enzymes at the level of the gene. Bacteria represent a relatively simple but exceedingly elegant system to study how one such response comes about, since, if a microbe is to compete and survive, it must respond rapidly and accurately to constantly changing environmental conditions, including availability of the kind and amount of nutrients.
The lac operon of E.coli has been one of the most widely studied and frequently used systems in bacterial genetics. Ever since the classical paper by Jacob and Monod (1961) elucidated the basic nature of its control elements, lac has served as a paradigm for gene regulation.
In order to fully understand the rationale and design of this experiment and to understand and analyze the results, it is important for you to study the reference material on:
1. the common modes of regulation
2. biochemical nature of lactose metabolism
3. history of the lac operon model
4. negative and positive control in the lac system
5. physical structure of the lac system
B. BACKGROUND COMMENTS REGARDING EXPERIMENT
b-galactosidase is an enzyme which hydrolyzes b-D-galactosides. After addition of the gratuitous inducer, isopropylthiogalactoside (IPTG; a non-metabolizable analog of lactose) to growing E.coli, active b-galactosidase molecules are synthesized after a lag of 1.5 - 2.0 min. During this time, the repressor-operator complex dissociates and a specific mRNA is transcribed and translated into b-galactosidase monomers, which are then assembled into active oligomers.
This protocol describes a simple assay for induced
b-galactosidase in situ that is easily done in class; it is a powerful way to illustrate regulation of gene expression. Once the enzyme has been induced (e.g. by IPTG), it is detected by assaying the enzymatic conversion of substrate (lactose or a derivative of lactose) into a (detectable) product. In this case, it can easily be measured with chromogenic substrates: i.e. colorless substrates which are hydrolyzed to yield colored products. An example is o-nitrophenyl-b-D-galactoside. This compound is colorless, but in the presence of b-galactosidase it is converted to galactose and o-nitrophenol. The o--nitrophenol is yellow and can be measured by its absorption at 420 nm. If the o-nitrophenol-b-D-galactoside (ONPG) concentration is high enough, the amount of o--nitrophenol produced is proportional to the amount of enzyme present and to the time the enzyme reacts with the ONPG. In order for the assay to be linear, the ONPG must be in excess. For best results, the amount of enzyme should be such that it takes between 15 minutes and 6 hours for a faint yellow color to develop. The reaction is stopped by adding a concentrated Na2CO3 solution, which shifts the pH to 11. At this pH, b-galactosidase is inactive.
An optional extension to this is to use the assay to actually study the process of induction: the experiment is designed to follow the
b-galactosidase synthesized by a growing culture after the addition of IPTG. One purpose of this experiment is to use the data to determine the kinetics of "z-mRNA" synthesis during induction. We will see that the induction of mRNA starts without any measurable lag; or in other words, the maximal rate of transcription is instantaneously achieved. (Note: if you elect not to carry out this experiment, you may use the data obtained by us to make these calculations.)C. PROTOCOL
1. Materials
E. coli MM294 (i+z+y+)
minimal growth medium:
For 10X stock solution of salts (per liter):
105g K2HPO4 (60.3mM)
45g KH2PO4 (33.1mM)
10g NH4SO4 (75.7mM)
5g Na3citrate-3H2O (16.0mM)
sterilize by autoclaving; store at room temperature
To make one liter of minimal growth medium, add:
100 ml 10X salt stock solution
20 ml of a 20% sterile solution of glucose (to give 0.4%; 0.5% if using glycerol)
1 ml of a sterile 1M MgSO4 solution
2 ml of a sterile 1% vitamin B1(thiamine hydrochloride) solution
reaction buffer (per liter)
Na2HPO4-7H2O 16.1g (60.1mM)
NaH2PO4-H2O 5.5g (39.9mM)
KCl 0.75g (10mM)
MgSO4-7H2O 0.246g(1mM)
2-mercaptoethanol 2.7ml (50mM)
adjust to pH 7.0; do not autoclave; store in refrigerator
ONPG: 4 mg/ml in 1X salts (above; can be frozen @ -20oC for several months)
IPTG: 0.01M in water
Na2CO3: 1M
0.1% SDS
chloroform
2. Procedure
a. Preparation
1) Two days prior to the experiment, streak out cells for single colony isolation on glucose- minimal medium agar.
2) One day prior to the experiment, prepare overnight cultures MM294 in:
a) glucose-minimal medium
b) lactose-minimal medium
c) glycerol-minimal medium
3) On day of experiment, dilute each overnight culture in fresh medium (e.g. 1/10-20) and grow to a titer of 2-5 x 108 cells/ml (i.e. O.D.600 of 0.3-0.70) . (e.g. 50 ml culture in a 250 ml flask, growing with aeration and at 37oC.)
4) While cultures are growing, prepare 4 reaction tubes for each culture, containing:
1 ml reaction buffer
2 drops SDS 4 drops chloroformb. Reaction1.) When the cultures reach the desired density, record the O.D.600. At that point, remove a 1.0 ml aliquot from each culture and start the timer (e.g. stopwatch). Add the removed aliquots to separate "t=0" reaction tubes; continue to incubate the remainder of the culture at 37oC with shaking. At t = 3 min., add IPTG to each culture. At t = 5, 15, and 30 min., remove 1.0 ml aliquots from each culture and add to the appropriately marked reaction tubes. 2.) After collecting the t = 30 min samples, measure the OD600 again (comparing this with the value obtained at the beginning of the experiment will tell you how much the culture has grown during the experiment; this information is important in making the calculations discussed later). 3.) To each reaction tube, add 0.4 ml ONPG and start your stopwatch. Incubate the tube at room temperature until you can see a yellow color develop OR 30 min.....whichever comes first. AT THAT POINT, ADD 1.0 ML OF THE NA2CO3 SOLUTION TO STOP THE REACTION; STOP YOUR STOPWATCH AND RECORD THE TIME. For a control, prepare a tube with twice the volume of reaction buffer, add ONPG, incubate and add Na2CO3 (this is to determine the extent to which ONPG hydrolyzes spontaneously). c. Assay1) For each tube, record the O.D.420; ideally, this (yellow color) reading should be 0.6-0.9. Record the OD550. The reading at 420nm is actually a combination of absorbance by the o-nitrophenol and light scattering by the cell debris. The latter component can be minimized (in the case of high levels of
b-galactosidase) by assaying more highly diluted cultures or it can be virtually eliminated by transferring the reaction mixture to plastic microfuge tubes, centrifuging for several minutes, and carefully transferring the supernatant with a pasteur pipet to a new spectrophotometer cell. Alternatively, the light scattering can be corrected for by obtaining the absorbance at another wavelength (550 nm) at which there is only light scattering by debris (no absorbance contribution from o-nitrophenol). The light scattering at 420nm is proportional to that at 550nm: for E.coli, the OD420 light scattering = 1.75 x OD550. Using this correction factor, which compensates for the light scattering, the true absorbance of the o-nitrophenol can be computed. Enzyme units are calculated according to:D. PROTOCOL FOR OPTIONAL EXPERIMENT: DETERMINATION OF THE KINETICS OF
b-GALACTOSIDASE PRODUCTION.1. Materials
E. coli MM294 (i+z+y+)
minimal growth medium:
For 10X stock solution of salts (per liter):
105g K2HPO4 (60.3mM)
45g KH2PO4 (33.1mM)
10g NH4SO4 (75.7mM)
5g Na3citrate-3H2O (16.0mM)
sterilize by autoclaving; store at room temperature
To make one liter of minimal growth medium, add:
100 ml 10X salt stock solution
20 ml of a 20% sterile solution of glycerol
1 ml of a sterile 1M MgSO4 solution
0.5 ml of a sterile 1% vitamin B1(thiamine hydrochloride) solution
reaction buffer (per liter)
Na2HPO4-7H2O 16.1g (60.1mM)
NaH2PO4-H2O 5.5g (39.9mM)
KCl 0.75g (10mM)
MgSO4-7H2O 0.246g(1mM)
2-mercaptoethanol 2.7ml (50mM)
adjust to pH 7.0; do not autoclave; store in refrigerator
ONPG: 4 mg/ml in 1X salts (above); prepare fresh
IPTG: 0.01M in water
Na2CO3: 1M
0.1% SDS
chloroform
2. Procedure
a. Preparation
1) Two days prior to the experiment, streak out cells for single colony isolation on glucose- minimal medium agar.
2) One day prior to the experiment, prepare overnight cultures MM294 in glycerol-minimal medium
3) On day of experiment, dilute the overnight culture in fresh medium (e.g. 1/10-20) and grow to a titer of 2-5 x 108 cells/ml (i.e. O.D.600 of 0.3-0.70) . (e.g. 50 ml culture in a 250 ml flask, growing with aeration and at 37oC.)
4) While the culture is growing, prepare a series(e.g. 12) of reaction tubes containing:
1 ml reaction buffer
2 drops SDS
4 drops chloroform
(These tubes will be used for samples removed from the growing culture, taken before and after addition of the inducer, IPTG.)
b. Reaction

1) When the culture reaches the desired density, record the O.D.600. At that point, remove a 1.0 ml aliquot from the culture and start the reaction timer (e.g. stopwatch). Add the removed aliquot to the "t=0" reaction tube; continue to incubate the remainder of the culture at 37oC with shaking.4 The remainder of the experiment involves removing additional 1 ml samples at t = 1,2,4,5,7,9,12,18,24,&32 with induction by addition of IPTG to the culture at t = 3.
After collecting all samples at the indicated times, measure the OD600 again (comparing this with the value obtained at the beginning of the experiment will tell you how much the culture has grown during the experiment; this information is important in making the calculations discussed later).
To each tube add 0.4 ml ONPG and start your stopwatch. Incubate the tube at room temperature until you can see a yellow color develop OR 30 min.....whichever comes first. AT THAT POINT, ADD 1.0 ML OF THE NA2CO3 SOLUTION TO STOP THE REACTION; STOP YOUR STOPWATCH AND RECORD THE TIME. For a control, prepare a tube with twice the volume of reaction buffer, add ONPG, incubate and add Na2CO3 (this is to determine the extent to which ONPG hydrolyzes spontaneously).
c. Assay and Analysis
1) For each tube, record the O.D.420; ideally, this (yellow color) reading should be 0.6-0.9. Record the OD550.
The reading at 420nm is actually a combination of absorbance by the o-nitrophenol and light scattering by the cell debris. The latter component can be minimized (in the case of high levels of b-galactosidase) by assaying more highly diluted cultures or it can be virtually eliminated by transferring the reaction mixture to plastic microfuge tubes, centrifuging for several minutes, and carefully transferring the supernatant with a pasteur pipet to a new spectrophotometer cell. Alternatively, the light scattering can be corrected for by obtaining the absorbance at another wavelength (550 nm) at which there is only light scattering by debris (no absorbance contribution from o-nitrophenol). The light scattering at 420nm is proportional to that at 550nm: for E.coli, the OD420 light scattering = 1.75 x OD550. Using this correction factor, which compensates for the light scattering, the true absorbance of the o-nitrophenol can be computed. Enzyme units are calculated according to:
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The OD420 and OD550 are read from the reaction mixture. The OD600 reflects the cell density just before assay; t = time of the reaction in minutes, and v = the volume of the culture ( in ml) used in the assay. These units are proportional to the increase in o-nitrophenol per minute per bacterium. They are convenient because a fully induced culture grown on glucose has approximately 1000 units and an uninduced culture has approximately 1 unit.
2.) The specific activity of b-galactosidase is defined in terms of units/mg protein. Many investigators define a unit of b-galactosidase as the amount of enzyme which produces 1nmole o-nitrophenol/min at 28oC, pH 7. Under the above conditions, 1 nmole/ml o-nitrophenol has an OD420 = 0.0045 using a 10 mm light path. Therefore the above units can easily be converted into these units. Although protein is usually determined directly from extracts of estimated from the dry weight of cells, we can estimate the amount of protein by assuming that 109 cells yields approximately 150 mg protein, and that an OD600 of 2.0 corresponds to 109 cells/ml. Using this information, calculate the specific activity of b-galactosidase in terms of nmoles o-nitrophenol/min/mg protein. (Using these parameters, calculations in the literature indicate that 3 activity units shown above correspond to 1 specific activity unit ). Given below are data from an experiment done in our lab.
|
growth time of culture (min) |
OD420 |
OD550 |
start reaction assay time (sec) add ONPG |
end reaction assay time (sec) add Na2CO3 |
total reaction assay time (min) |
Units b-gal per ml |
|
0 |
0.52 |
0.305 |
4 |
967 |
16.05 |
-2.2 |
|
1.22 |
0.511 |
0.318 |
10 |
964 |
15.9 |
-7.6 |
|
3.12 |
0.437 |
0.261 |
16 |
982 |
15.77 |
-3.3 |
|
5.18 |
0.647 |
0.27 |
21 |
960 |
15.65 |
29.5 |
|
7.82 |
0.802 |
0.25 |
77 |
364 |
4.78 |
254.8 |
|
9.15 |
0.825 |
0.202 |
85 |
366 |
4.68 |
266.2 |
|
12.23 |
1.462* |
0.211 |
100 |
370 |
4.5 |
641.6 |
|
17.00 |
1.895* |
0.208 |
165 |
437 |
4.53 |
894.7 |
|
22.1 |
1.778* |
0.158 |
170 |
442 |
4.53 |
875.7 |
|
27.18 |
2.928* |
0.236 |
176 |
450 |
4.57 |
1556.3 |
|
33.15 |
2.748* |
0.232 |
293 |
516 |
3.72 |
1663.3 |
|
33.23 |
2.914* |
0.246 |
297 |
520 |
3.72 |
1763.8 |
* samples diluted 1:10 for OD measurement; value = reading x 10
3.) Plot the results: units of
b-galactosidase vs. time (starting a t = 0). By extrapolating your plot to the x-axis, determine how long it took your cells to synthesize b-galactosidase after addition of the inducer, IPTG. The b-galactosidase monomer is approximately 1170 amino acids long (135,000 daltons). If the first active tetramer appears at the time indicated by the x-intercept of your graph, what is the rate of chain elongation of this polypeptide, in amino acids per second? (Be careful....does it take four times as long to make the tetramer as the monomer?) If transcription and translation are coupled, what is the rate of synthesis of "z-mRNA", in bases per second?E. FOR THOUGHT AND DISCUSSION
1.) One of the methods bacterial geneticists used to deduce how the lac system works was to create partial diploids. To do this, they constructed strains by conjugation that contained a genotype determined by the chromosomal lac operon and the lac operon residing on an F' plasmid. By carrying out the assay experiment you have done, using combinations of genotypes with mutations in the "o", "i", and "z" regions, they were able to deduce how the regulatory system worked. Below is a table listing the various partial diploids having several combinations of lacI and lacO alleles. For each construction, predict whether it results in a phenotype that is constitutive or inducible with respect to lac mRNA synthesis.
|
genotype |
constitutive (c) or inducible (i) |
|
F'lacOclacZ+ / lacO+lacZ+ |
|
|
F'lacO+lacZ+ / lacOclacZ+ |
|
|
F'lacI-lacZ+ / lacI+lacZ+ |
|
|
F'lacI+lacZ+ / lacI-lacZ+ |
|
|
F'lacOclacZ+ / lacI-lacZ+ |
|
|
F'lacOclacZ- / lacO+lacZ+ |
|
|
F'lacOclacZ+ / lacO+lacZ- |
/Taken from the UW-Madison Bacteriology 304 Lab Manual, by Dr. Tim Paustian)
Regulation of ß-galactosidase activity in Escherichia coli:
Induction of the lac Operon
All organisms need to be able to respond to changes in the environment around them and even bacteria are capable of regulating their metabolism depending upon conditions. When nutrients become available, a microorganism must be able to respond to and use them for growth, if the microbe is to compete and survive. A response to changes in the environment is often dependent upon the de novo production of enzymes to metabolize the nutrient in question. This is termed enzyme induction. The
b-galactosidase operon was one of the first induction systems studied. A major study by Francois Jacob and Jacques Monad was seminal to our present understanding of bacterial gene regulationThe system investigated by Jacob and Monod involved the utilization of lactose by Escherichia coli. Lactose is a dimeric sugar and is acted on by the enzyme ß-galactosidase (
b-gal), which adds water to the b-linkage, splitting it into glucose and galactose (Fig. 1). The products of this reaction are then metabolized via glycolysis. When lactose is not present in the environment, b-gal cannot be detected inside the cell. If lactose is added a 500-1000 fold induction of b-gal is observed. How does this induction take place?
Figure 1. The enzymatic degradation of lactose by
b-gal.Genetic Organization of the Lactose Operon
To understand how
b-gal is induced, it is first necessary to know the organization of the genes involved in the process. The lactose operon (Figure 2) is composed of 3 genes. b-galactosidase is coded for by the lacZ gene. The lacY gene codes for galactose permease, an enzyme responsible for the transport of lactose across the cellular membrane. The lacA gene codes for the production of the thiogalactoside transacetylase, whose purpose in lactose metabolism remains unknown. (When looking at almost any research problem there are always unanswered questions, such as lacA. That's what makes science fun!) The gene for the repressor of the lactose operon, lac I, is located upstream of the lacZYA genes.
Figure 2. The lactose operon. The straight line at the top of the figure represents a cartoon of the DNA. The transcription of the operon by RNA polymerase is blocked by the lac repressor. Inactivation of the lac repressor by allolactose allows the production of lac mRNA and the expression the lac enzymes.
lacZ, Y, and A are transcribed by RNA polymerase from one promotor (plac) located upstream of the lacZ gene. When lactose is not present the repressor binds to the operator sequence, located between plac and lacZ, and prevents RNA polymerase from binding and transcribing the lac mRNA. When lactose reaches the cell, ß-gal acts on it. Hey! wait a minute!, How can there be ß-gal in the cytoplasm when the operon is turned off? Remember, there are no absolutes in regulation or in science. A small amount of transcription must be coming from the lac operon, so there is a low concentration of ß-gal and lactose permease in the cell, even when the repressor is in binding mode. Thus lactose in the environment is transported into the cell and then acted on by the low concentration of ß-gal. ß-gal converts lactose to glucose and galactose, but a small portion is converted to a side product, allolactose. The allolactose binds to the repressor in its effector site and causes it to fall off the operator site. Transcription by RNA polymerase then proceeds and the operon is induced.
There is another separate level of regulation on the lactose operon. A positive activator, cyclic AMP receptor protein (CRP), must also bind near the promotor to get significant transcription. This protein is activated by a high level of cyclic AMP (cAMP). The concentration of cAMP is high when the cell is starving for energy (for example, when the cell is in an environment lacking a carbon source). When cAMP is high, it binds to CRP protein and activates it. The cAMP–CRP complex then binds to many sites in the chromosome, one of them being the lactose operon. To activate the lactose operon, the level of cAMP must be high (the cell is starved for energy) and lactose must be present. If glucose is present, the level of cAMP is low and the lactose operon is not induced, even if lactose is present. In this way the bacterial cell does not waste energy synthesizing proteins involved in degradation of lactose when a better carbon source, glucose, is available.
Introduction to the measurement of enzyme activity
Inthis experiment, the amount of
b-gal present in the cell will be used to gauge the activity of the lactose operon and illustrate its regulation. How will b-gal activity be measured? We will use an enzyme assay.An enzyme is a protein that catalyzes a biochemical reaction. Measurement of enzymes is accomplished by adding the compound the enzyme acts upon (called a substrate) to a reaction mixture containing everything necessary for the reaction to take place (protein, ATP, cofactors, etc.). The enzyme then acts on the substrate converting it to product. In one type of assay, (the kind we will be using) the increase in product or the decrease in substrate is monitored over a set time period. The final amount of product produced, or substrate lost, in a certain amount of time is proportional to the concentration of the enzyme and is often used to quantitate the amount of an enzyme present. This is termed an end-point assay. As an example, for
b-gal, the substrate lactose, could be added to the enzyme in solution and the production of glucose or galactose could be measured.Good enzyme assays have several features in common 1) absolute specificity, 2) high sensitivity, 3) accuracy and precision, 4) convenience. However, the in vivo substrates and products of the
b-gal catalyzed reaction are all colorless. These products would be difficult to measure and this violates the convenience aspect of a good assay. Instead, an artificial substrate, ortho-nitrophenyl-b,D-galactoside (ONPG), is used (Figure 3). ONPG is a colorless compound that is split at its galactoside bond into galactose (colorless) and ortho-nitrophenol (ONP, which is an intense yellow color at high pH) by b-gal. The concentration of ONP can be measured using a spectrophotometer and related back to enzyme activity.Enzyme activity is represented in units, which is defined as the number of micromoles of substrate converted to product in 1 min., usually at 30°C. The units of
b-gal activity can be calculated using the concentration of ONP. See the end of this experiment for details.
Figure 3. The splitting of ONPG into galactose and ONP by ß-gal.
In this experiment you will first learn how to perform one type of enzyme assay, an end-point assay and in the second part, the induction of
b-gal activity in two E. coli strains will be followed under different conditions.
Protocol
Period 1
Materials
Dropper bottle of toluene
2 tubes of ortho-nitrophenyl-
1 bottle
b-gal buffer1 bottle stop solution
6 13 x 100 mm test tubes
Cultures of:
E. coli grown in Minimal Medium + Lactose
E. coli grown in Minimal Medium + Glucose
Today you will be practicing the
b-gal assay. We will be performing this now so that next period, when time is limited, you will be old pros at the assay and it will not slow you down during the induction experiment.1. Label the 6 tubes glucose 1, glucose 2, glucose blank, lactose 1, lactose 2, and lactose blank. Place 1 ml from the glucose culture into each of the three glucose tubes. Put 1 ml of the lactose culture into each of the three lactose tubes. To the four assay tubes (glucose 1 and 2, lactose 1 and 2), add 1 ml of
2. Add 1 drop of toluene to the six tubes and vortex each tube vigorously for 1 minute. The toluene permeabilizes the cells and allows substrates and products to pass in and out.
3. Place the four assay tubes in front of you–ONPG will not be added to the blanks. Instead add 1 ml of
b-gal buffer to each blank. Prepare your timer by turning it on and pushing the reset button, or use the clock. As you add 1 ml of ONPG to the first assay tube, start the timer. Continue adding ONPG to the other tubes, noting the time delay for each addition.4. Watch the reactions in each assay carefully. When an obvious yellow color develops in a tube (this takes several minutes) add 1 ml stop solution to the tube and make note of the time. With tubes other than the first one, remember to compensate for the time taken to add ONPG to the tubes after the timer was started. This assay is an end-point assay because after a set amount of time, stop solution is added inactivating
b-gal and ending the reaction. (Why is it also necessary to add stop buffer to your blank?) If a tube has not changed color in 5-10 minutes stop the assay.[Optional - you may want to centrifuge your sample to remove the cells which can interfere with absorbance readings]
5. After zeroing the spectrophotometer, read the absorbance of the solution at a wavelength of 420 nm. Wait for a constant absorbance reading on the spectrophotometer.
6. Using a separate sample from the two E. coli cultures, measure the turbidity of the culture at a wavelength of 600 nm as in experiment 4. Use a sample of fresh medium and an appropriate blank. This reading is an estimate of the number of cells in the culture. (During calculation of
7. Calculate the units of
b-gal/ml/A600 in the sample using the formula at the end of this experiment.Period 2
Materials
1 500 ml flask with 200 ml of Minimal Medium (MM) + 0.2% Glucose
or
1 500 ml flask with 200 ml of MM + 0.2% Lactose
1 Dropper bottle of toluene
2 tubes of ONPG
1 bottle
1 bottle stop solution
Basket on 13 x 100 mm test tubes (non-sterile)
Stationary phase cultures of E. coli strain 1 or E. coli strain 2 grown in MM + Glucose
In this experiment, each pair will test for the induction of
b-gal under one of the following conditions:• Strain 1 in Minimal Medium + Lactose
• Strain 1 in Minimal Medium +Glucose
• Strain 2 in Minimal Medium + Lactose
• Strain 2 in Minimal Medium +Glucose
These two strains have different phenotypes for lactose utilization. In the experiment, you will investigate these phenotypes. After analysis of the data and careful consideration of the genetics of the lac operon, it will be possible to hypothesize about the genotypes of the two strains. Each pair of students will be responsible for monitoring one flask. Divide the labor between the two of you (i.e. one person reads A600, the other performs the
b-gal assay). The data generated in this experiment is most easily recorded in tabular form.Flasks of MM + lactose and MM + glucose have been pre-warmed in the 37°C water baths for you. Why was this done?
1. Record whether the flask assigned to you contains lactose- or glucose-minimal medium and whether you were provided with strain 1 or 2.
2. Inoculate your flask by pouring in 5 ml of overnight culture given to you. When inoculating, do not withdraw the 500 ml flask from the water bath. After mixing remove 5 ml of culture for the t0 time point. Turn on the shaker.
3. With 2 ml of the sample, begin the
b-gal assay as performed in period 1. One ml of the culture should be used for the assay, another for the blank. Use a new blank for each sample. Why?4. Measure the absorbance of the diluted culture at 600 nm. If the absorbance is greater than 0.5, dilute 1 ml of the sample with 3 ml of fresh media (a 4-fold dilution). Do not forget to multiply by 4 when recording your results for diluted samples.
5. Take samples every 15 min. Do not remove the flask from the shaker or change the shaking rate when removing samples. Take an A600 reading and perform a
b-gal assay on each sample.7. Monitor the absorbance and
b-gal activity for 8 time points (1.75 hr.).8. Before next period calculate the units of
b-gal/ml•abs for each time point as explained at the end of this experiment.Period 3
Data analysis and computer graphing
1. Get data for the three conditions that you did not do from other lab groups. Make sure you have a full set of data.
2. Using a computer, plot
3. Include graphs of all four conditions in your lab notebook. Try and finish your graphs before next period, when graphing methods will be discussed by your instructor.
How to Calculate ß-galactosidase Activity
Step 1 - Determining the concentration of ONPG in the assay tube.
To calculate
b-gal activity for this experiment gather together the A420 reading from the b-gal assay, the A600 turbidity reading, and the elapsed time of the assay. It is very useful to organize your data into a table. For example....|
Time |
A420 |
A600 |
Time of assay |
U/ml |
U/ml/A600 |
|
0 |
0.200 |
0.113 |
1 min. |
||
|
15 |
0.400 |
0.200 |
0.75 min. |
||
|
30 |
0.600 |
0.600 |
1 min. |
||
|
etc. |
The first value to calculate is the concentration of ONP (a product of the reaction) in the assay tube. To do this, use Beer's Law, which is...
![]()
or ![]()
where
A = Absorbance (at 420 nm for this experiment).
e
= The extinction coefficient (1.1 x 103 ml/µmole•cm)c = The concentration of the colored compound (o-nitrophenol)
l = The length of the light path (1 cm for most spectrophotometers)
Step 2 - Determining the concentration of ONPG/ml of culture
The goal is to compare the activity of
b-gal in each strain. To derive b-gal activity, we next calculate the total amount of product in the tube, ending up with µmoles. To do this, multiply the total volume of the assay (in ml) by the concentration of ONP calculated in step 1.Step 3 - Units of ß-gal/ml of culture
A unit of enzyme activity is defined as the amount of enzyme it takes to produce 1 µmole of product/min. (usually at 30°C, but for this experiment we will use room temperature). From step 2 the µmoles of ONP split in the assay is known. To calculate the units/ml, just divide by the time of the assay.
Step 4 - Units of ß-gal/ml•A600
Finally, to be able to compare cultures at different time points that have different numbers of cells (different A600 readings), it is important to normalize the values by dividing by A600. Take the number from step 3 and divide by the absorbance.
Example Calculation:
The data
|
A600 of culture |
A420 of assay |
Time of assay (min.) |
|
0.220 |
0.346 |
1 min. 20 s (= 1.33 min.) |
Step 1
Beers Law ![]()
Step 2
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Step 3 and Step 4![]()
Questions
1. In period 1 of this experiment, which culture, E. coli grown with lactose or E. coli grown with glucose, had more
b-galactosidase activity? Can you explain this?2. Do you think there were errors in your data. Why or why not? Can you identify the cause of the errors?
3. Describe the behavior of each strain under the two conditions. In which strain was
b-gal apparently induced? Explain your answer.4. One of the strains used in this experiment contains a mutation in the lac system. Which one do you think it is? Give evidence to support your answer.
5. For the mutant strain, suggest where in the lac system the mutation might be. There are two possibilities. Using what you know about the regulation of the operon, explain how this mutation would result in the effects you observed in this experiment.